print (1 ? 1 : 0) . 'x'

[Stig Brautaset]

On 11 May 2006, at 10:59, O'Shaughnessy, Jamie wrote:

>
> print (1 ? 1 : 0) . 'x';
>
> What do you expect this would print?
>
> I expected the output would be "1x" - the ?: evaluates to 1, the () 
> s are needed because . Is higher precedence than ?: so you end up  
> with 1 . 'x' as the parameter to print - hence print "1x".
>
> However it doesn't, it just prints "1".

... and the return value from print is concatenated with 'x'; if you  
use warnings you'd probably get a diagnostic.

The brackets are used there to delimit the function call, so it  
basically boils down to:

   print(1) . 'x';


Stig