Assigning anonymous hash to a list

[Hernan Lopes]

When you do that, you are implicitly saying:

The thing on the left is equals the thing in the right.
So, in the left you have 1 thing ( a list because of parenthesis ),
and on the right, you have 2 things: string+object.

Add parenthesis on the right and transform it into a list.

After that perl will understand you are assinging the first thing on
the list (from left) equals the first thing on the list (from right)
and so on.

[]'s

Hernan Lopes

On 7/30/13, gvim <gvimrc at gmail.com> wrote:
> Can anyone explain why this works:
>
> my $ref = {a => 1,  b => 2, c => 3};
> say $ref->{b};     #  Result: 2
>
> ... but this doesn't :
>
> my ($str, $ref) = 'text', {a => 1, b => 2, c => 3};
> say $ref->{b};   # Result: Use of uninitialized value
>
> Seems a little inconsistent.
>
> gvim
>